formula for aircooling lights?

  • Thread starter RacecarRandy
  • Start date
  • Tagged users None
RacecarRandy

RacecarRandy

34
8
I remember seeing a formula for air cooling lights a while back and cant find it for the life of me. if anyone could post this I would be very grateful.
I am trying to figure out what cfm fan to get for aircooling 2 1000 watts that are run in a series. they will draw air from a lung room (72 degrees) and exhaust to an attic.
thanks
 
K

Kief Stoned

172
0
Grab a decent 8 inch inline and be done with it. No forumla needed. Easy peasy. I use a single 6 inch for my 2 600W air cooled hoods.
 
J

Jsän

168
0
NOT MY WORK, JUST A C&P..props go to whoever the OP was.
remember this is just the theoretical Minimum.

**Overheating is a common problem encountered by growers, especially in closet or 'box' setups. High temperatures cause whispy buds and is often a sign of inadequate ventilation, which brings a whole host of other problems.

Whether at the design stage or struggling with an existing problem, the following formula can be useful in assessing your situation. Its pretty basic in terms of heat transfer but from experience has proved to be pretty accurate for our purposes.

The formula is:

Q = V x P x C x dT

where:
Q = Amount of lighting (kW)
V = Volume of air being ventilated (m3/s)
P = Density of air (assume 1.2 kg/m3)
C = Specific heat capacity of air (assume 1.02 kJ/kgK)
dT = Temperature difference between ambient and growspace air in degC

You can use this to determine what the temperature rise in your space will be (dT), or given a desired temperature rise you can use it to work out how much ventilation you will require (V)

To get from CFM to m3/s divide the CFM by 2119.

Examples
Here are some examples of how you could use the formula in three different ways, each using the same basic figures for clarity.

What temperature am I likely to get in my growspace?
Assume: Lighting = 400W (0.4kW), ventilation = 240m3/hr (0.067m3/s) and temperature of air entering room = 21degC

Q = V x P x C x dT
=> dT = Q / (V x P x C)
=> dT = 0.4 / (0.067 x 1.2 x 1.02)
=> dT = 4.87, i.e. 21 + 5 = 26degC in growspace

How much ventilation am I likely to need?
Assume: Lighting = 400W (0.4kW), temperature of air entering room = 21degC and temperature of growspace to be no more that 26degC

Q = V x P x C x dT
=> V = Q / (P x C x dT)
=> V = 0.4 / (1.2 x 1.02 x (26-21))
=> V = 0.065 m3/s i.e. 240 m3/hr

What is the most lighting I can put into my growspace?
Assume: Ventilation = 240m3/hr (0.067m3/s), temperature of air entering room = 21degC, temperature of growspace to be no more that 26degC

Q = V x P x C x dT
Q = 0.067 x 1.2 x 1.02 x (26-21)
Q = 0.41 kW i.e. 400 W

So that’s it, once you get used to using it its very simple really, Just stuff the formula and figures in a spreadsheet and let it do the work.****


Greens and Luck
 
K

Kief Stoned

172
0
lol.. I am always taken aback at how anal some people get over stuff. Now, i'm sure a formula like that would cut out alot of trial and error when it comes to a setting up a huge grow op ( IE - 10 lights or more etc etc ) , but for just 2 lights its just not needed in my opinion...I dont need Rube Goldberg to design my lighting lol.. I prefer the K.I.S.S. formula.. Keep It Simple Stupid.. lol
 
Top Bottom