You keep saying watts have nothing to do with it and won't prove anything, so, could you please explain to me (in lamest terms) how more watts do not generate more light intensity when it comes to HID grow lights. Also, I honestly dont know how else to explain light strength in HID's other than watts.
Happy to.
Okay so let's assume that we're going to run this experiment for the following argument:
Let's start at the beginning and be specific about the question we're asking (or our hypothesis). So what we want to find out is: can we use less electricity without losing yield?
If we want to answer this question for
your and only your setup (or an identical one) then using wattage is fine, because all of your results are quantified according to
your wattages. So if you notice that you set this at 600W rather than 1000W and you can still yield the same and thus save on electricity.
Now, that's a great finding--and it will aid you greatly and save you money. If that's your plan then I encourage you and wish you luck. I think it's a great idea.
However, if you want to answer this question
for everyone you need to put it into a value which is easily measurable for all. Because of the many many different lighting fixture/bulb designs in HID lighting every light/bulb will not be producing the same intensity/density of light as other designs.
So if someone wanted to repeat your results--and they try to use 600W as you did, they may end up sacrificing some yield if their density/intensity values are not the same as yours were.
In science, we report the value that matter
to the system not the one that is easiest for us. A plant does not care what wattage produced a light of a given density/intensity--it only cares about the density/intensity. Because of this it could be misleading, or un-useful, for someone else to attempt to repeat your results using wattage as a guide.
You can say:
A plant which is exposed to light of density X and intensity Y will still produce a given yield Z under certain circumstances. If you measure these quantities (and if we do enough experiments and find a representative mean for the population) then we can say some
definitive things about how intensity/density of light will affect yield and whether or not we can save on electricity.
You cannot say:
A plant which is exposed to light produced by wattage X will produce a given yield Z as compared with a light produced by wattage Y.
The reason you can't say this is that the
physical quantities which are important to the plant are independent of wattage. Wattage
can effect a given light in a predictable way, but we can only make predictions for
that light if we choose to base an experiment like this off of wattage.
I suppose in most layman terms I'd say the following:
Less wattage does translate to less intensity--but the reduction in intensity for a given wattage
is not a constant term which applies to all lights. If you switch one light from 1000 to 600, it may drop the intensity by X. If you switch another from 1000 to 600 it may drop the intensity by Y (a different value).
For this reason it is more useful to discuss the intensity/density as these should average out to be
constant values for the given experiment which will apply to all plants of a given genetic profile. These are the values the plants care about.
Here's an analogy if you're still having trouble.
The velocity of a given gaseous particle is dependent upon (in a simple case) two things. Temperature and pressure. Essentially the higher the temperature the faster particles are moving in the gas phase.
Doing this experiment this way and measuring wattage would be a lot like doing an experiment in which you wanted to test the effects of varying temperature--but instead of deciding to measure the temperature of the room to record, you decide to instead measure the velocity of a given particle.
This would be okay if the velocity depended
only on the temperature, but in this case it actually depends also on the pressure (and concentrations of particles). If the experiment in question was involving a plant we could measure the same velocity for a particle (if we varied the pressure) and observe temperatures which cover the entire range of the plants ability to survive so all the way from fatally low temperatures to fatally high temperatures (with the same velocity). If I were to hold pressure/concentrations constant then the same velocity would always translate to the same temperature--and this is analogous to the situation above wherein measuring wattages will work for
your and only your lights. For this experiment the velocity measurements would work for
my and only my pressures.
The same thing
could happen here. We could be covering the entire range of intensities/densities from no response to negative response, if we use enough different lights. However we have the technology to directly measure the physical quantities we're after and leave the light design and variance behind as a confounding variable and instead focus on these quantities.
Just for a heads up--the equipment to measure these quantities
does not cost thousands of dollars. I wouldn't have even brought this up if it did.