ttystikk
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Would have to get full load amp draw and figure kw/hr usage with amt of time unit runs per hour. With this you could get a close est of kw/ton. Then do the math on a 3 ton good quality inverter mini split. I have a feeling if the math is done right your savings may be less than what you imagine because your unit runs at full load when ever it runs and an inverter mini can match the load very precisely.
What up CJ? Miss ya Bro! Good to see ya around! Props on all the AC knowledge you drop Dawg! Much Respect!
I'm sorry, I think I was being unnecessarily confusing with all that- I didn't ask about the power consumption difference between a chiller cooling an airspace and a minisplit doing the same thing. That's a good question and I'll have to answer it sometime, but what I really want to know is how much the venting system that's cooling my hoods is saving me in cooling capacity- or cost, whichever. It occurs to me that I should just measure how much my chiller runs with it on, and then with it off, and subtract the two?
It may be impossible to do that. Sorry for misreading the initial question. Let's put it this way if your venting wasn't proper than you wouldn't cool correctly. Are your ice boxes inline with hood venting or do they just cool the room?
I'm glad you sked that question, because the single thing that bugs me the most about people trying to build a sealed room is when they try to cool their HID lighting directly, and wonder why they then need HUGE AC capacity, and spend HUGE amounts of money running it! And if that weren't enough, they spend a lot of time dealing with indirect effects of such overcapacity, like hot and cold spots, low humidity and electrical problems.
I run an aircooled setup to cool my lights; the air comes from outside the growroom, is ducted to each light (in this case two rows of four Ochos each), PULLED through the hoods, and then sucked out of the room. The fan that pulls the air through the hoods is sited as close to the exit as possible, as this drastically reduces heat buildup. There is no active cooling other than air to cool the lights, and none is needed because this air never mixes with the sealed room environment. Even if the air leaves the room at 120 degrees it's okay since... well, since it's leaving, right?
The working air in the room is then cooled by 2 maxfans each blowing through its own Ice Box, which removes residual heat from the hoods, radiant heat (the part the plants actually use), heat from fans, electronics, dehuey, CO2 burner, etc. These units are taped together and hung from the ceiling, so they just suck air in at one end and blow it back out into the room. I aim them down somewhat so they can blow cooled air down towards the plants and create a nice breeze while they run. Again, these fans are thrmostatically controlled by my environmental controller and run about half time when all the gear is on full blast. That warmed water then mixes with warmed water from my RDWC units and continues on to my chiller, where the heat is removed. My chiller is set for 52 with an 8 degree rise before it kicks on. Keeping the relative humidity in the growroom below 60% prevents condensation issues on waterlines and Ice Boxes.
When I asked you about sizing cooling capacity for this room originally, I remember your calculations were based on 8kW of unvented lighting in the room and you suggested that a 2 ton chiller might or might not quite keep up, but it would be close. With the aircooling, the chiller runs about half time, and it's cooling all the other loads I mentioned above as well. Therefore, it works, and it works very well.
The reason I asked the question I did is so that I can quantify how much cooling I'm gaining with this aircooled helper setup. Just telling people they will save an unspecified but 'large' amount of power isn't as convincing as saying something specific , such as they're looking at saving some 2/3 of their total bulb cooling requirement. As it stands, two-thirds is my best guess on how much heat the aircooled system removes from the lights. Combined with other energy saving strategies I'm working on, as discussed elsewhere in these forums, I'm trying to reduce a given grow's energy consumption footprint by a solid 50% per unit of output produced over currently practiced methods.
New readers please know we've hardly done justice to re-starting this thread compared to the previous one. Kind of makes me want to go dig through web archives to look for an old version..
So boxing in a condenser for ventilation, what would be a good thumb-rule for minimum interior volume per ton/12k?
CJ, did you notice my other question about inverters a few posts back? Just wondering if there are any downsides or contraindications compared to using regular mini?
Hello,
Thanks for having this thread for all us AC illiterate growers.
Quick question:
I have a 12k, bare bulb room going up. It will have a CO2 burner. Is this a good unit for me? 48,000 btu. I would put one handler on each wall.
I want to buy these cause the distributor is local.For repairs and warranties and such.
Many thanks.
I would say that somewhere around 2-3 sq ft of space per ton but make sure box is same or bigger dimensions than condenser coil is.
You mean cu ft? Sounds like not much plenum space necessary with proper vent-fan match?
Are there any window or small all-in-one units available inverter style? (did a quick search and not seeing anything on retail mkt)
John,how are you bro?,Can you tell me what size the pads need to be for the mini condensers to sit on?should they be right in front of the disconnect or off to one side or the other?thanks FW
thanks bro!
The problem with you are doing is that some people don't want to pay for hoods, ducting, and fans to vent lights. Also some people are running vertical lighting. I think the bottom line is everyone wants something different so I try to give them what they want.
Im gonna pour em in concrete as i have a set of steps to do to.No problem. Also you can buy outdoor pads pre-made for about $30 each or so.
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